1/, 98/, 4 4/ Fractions Average can be found easily using the online tool Fractions Average Calculator and get step by step procedure involved.
Given fractions are 1/,98/,174/
Arrange the Inputs 66,80,43 in a horizontal line separated by commas and divide them with a prime number. Note the quotients in the next row and divide with quotients with prime numbers again. Continue the process until you have all co primes in the last.
|2||66, 80, 43|
|33, 40, 43|
As all the numbers left in the last row are co primes you need not do the common division process further.
To obtain the Least Common Multiple, multiply the prime numbers with which you have divided the given numbers and the co primes in the last row i.e. 2 x 33 x 40 x 43 = 113520
Therefore, LCM of 66,80,43 is 113520
The least common Multiple (LCM) is: 113520.
Rewriting as equivalent fractions with the LCM:
Totaling the numerator:
Reducing the fraction:
Dividing by the number of values: 3
The given fractions are 300071/ and 3/
On dividing the both fractions,300071/ ÷ 3/
Then the denominator of the first fraction i.e., 56760 will comes to the numerator of the second fraction and gets multiplied,
And in the same way,the denominator of the second fraction i.e., 1 will comes to the numerator of the first fraction and gets multiplied:
300071/ ÷ 3/ = 300071 x 1/
On Multiplying the denominators and the numerators,the fraction value we get,
Average of fraction = 300071/
Here are some samples of Average of Fractions calculations.
1. What is the average of fractions 1/, 98/, 4 4/ ?
Average of Fractions is 300071/
2. How to find the Average of Fractions 1/, 98/, 4 4/ ?
Set up an addition equation with the given fractions 1/, 98/, 4 4/ and then find the LCD. Rewrite each of the fractions as equivalent fractions using LCD. Add the numerators and place the sum over the LCD and reduce it further.
3. Where do I find an elaborate solution to find the Average of Fractions 1/, 98/, 4 4/ ?
You can find the elaborate solution to find the Average of Fractions 1/, 98/, 4 4/ on our page.