HCF of 140, 75 by Euclid's Divison lemma method can be determined easily by using our free online HCF using Euclid's Divison Lemma Calculator and get the result in a fraction of seconds ie., 5 the largest factor that exactly divides the numbers with r=0.
Highest common factor (HCF) of 140, 75 is 5.
HCF(140, 75) = 5
Ex: 10, 15, 20 (or) 24, 48, 96,45 (or) 78902, 89765, 12345
Below detailed show work will make you learn how to find HCF of 140,75 using the Euclidean division algorithm. So, follow the step by step explanation & check the answer for HCF(140,75).
Here 140 is greater than 75
Now, consider the largest number as 'a' from the given number ie., 140 and 75 satisfy Euclid's division lemma statement a = bq + r where 0 ≤ r < b
Step 1: Since 140 > 75, we apply the division lemma to 140 and 75, to get
140 = 75 x 1 + 65
Step 2: Since the reminder 75 ≠ 0, we apply division lemma to 65 and 75, to get
75 = 65 x 1 + 10
Step 3: We consider the new divisor 65 and the new remainder 10, and apply the division lemma to get
65 = 10 x 6 + 5
We consider the new divisor 10 and the new remainder 5, and apply the division lemma to get
10 = 5 x 2 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 5, the HCF of 140 and 75 is 5
Notice that 5 = HCF(10,5) = HCF(65,10) = HCF(75,65) = HCF(140,75) .
Therefore, HCF of 140,75 using Euclid's division lemma is 5.
1. What is the HCF(140, 75)?
The Highest common factor of 140, 75 is 5 the largest common factor that exactly divides two or more numbers with remainder 0.
2. How do you find HCF of 140, 75 using the Euclidean division algorithm?
According to the Euclidean division algorithm, if we have two integers say a, b ie., 140, 75 the largest number should satisfy Euclid's statement a = bq + r where 0 ≤ r < b and get the highest common factor of 140, 75 as 5.
3. Where can I get a detailed solution for finding the HCF(140, 75) by Euclid's division lemma method?
You can get a detailed solution for finding the HCF(140, 75) by Euclid's division lemma method on our page.