HCF of 143, 35 by Euclid's Divison lemma method can be determined easily by using our free online HCF using Euclid's Divison Lemma Calculator and get the result in a fraction of seconds ie., 1 the largest factor that exactly divides the numbers with r=0.
Highest common factor (HCF) of 143, 35 is 1.
HCF(143, 35) = 1
Ex: 10, 15, 20 (or) 24, 48, 96,45 (or) 78902, 89765, 12345
Below detailed show work will make you learn how to find HCF of 143,35 using the Euclidean division algorithm. So, follow the step by step explanation & check the answer for HCF(143,35).
Here 143 is greater than 35
Now, consider the largest number as 'a' from the given number ie., 143 and 35 satisfy Euclid's division lemma statement a = bq + r where 0 ≤ r < b
Step 1: Since 143 > 35, we apply the division lemma to 143 and 35, to get
143 = 35 x 4 + 3
Step 2: Since the reminder 35 ≠ 0, we apply division lemma to 3 and 35, to get
35 = 3 x 11 + 2
Step 3: We consider the new divisor 3 and the new remainder 2, and apply the division lemma to get
3 = 2 x 1 + 1
We consider the new divisor 2 and the new remainder 1, and apply the division lemma to get
2 = 1 x 2 + 0
The remainder has now become zero, so our procedure stops. Since the divisor at this stage is 1, the HCF of 143 and 35 is 1
Notice that 1 = HCF(2,1) = HCF(3,2) = HCF(35,3) = HCF(143,35) .
Therefore, HCF of 143,35 using Euclid's division lemma is 1.
1. What is the HCF(143, 35)?
The Highest common factor of 143, 35 is 1 the largest common factor that exactly divides two or more numbers with remainder 0.
2. How do you find HCF of 143, 35 using the Euclidean division algorithm?
According to the Euclidean division algorithm, if we have two integers say a, b ie., 143, 35 the largest number should satisfy Euclid's statement a = bq + r where 0 ≤ r < b and get the highest common factor of 143, 35 as 1.
3. Where can I get a detailed solution for finding the HCF(143, 35) by Euclid's division lemma method?
You can get a detailed solution for finding the HCF(143, 35) by Euclid's division lemma method on our page.